Class 9 Maths Chapter 4 Exercise 4.3 Solutions Ganita Manjari 2026 Exploring Algebraic Identities

Class 9 Maths Chapter 4 Exercise 4.3 Solutions (Ganita Manjari 2026) – Exploring Algebraic Identities

📘 NCERT Ganita Manjari (2026) 📚 CBSE 2026–27 ✅ Step-by-Step Solutions

Class 9 Maths Chapter 4 Exercise 4.3 Solutions

Learn Class 9 Maths Chapter 4 Exercise 4.3 Solutions with easy, step-by-step NCERT solutions based on the latest Ganita Manjari (2026). In this exercise, you will learn how to choose the correct algebraic identity, find squares quickly, expand algebraic expressions involving three terms, factorise perfect square expressions, and verify algebraic identities according to the latest CBSE Class 9 syllabus and exam pattern.

📖
Exercise
4.3
Questions
4 (15 Parts)
🧠
Concept
Algebraic Identities
Difficulty
Moderate
⏱️
Study Time
30–40 Min
🎯
Exam Importance
★★★★★
📌 Main Identities Used Throughout This Exercise
(a + b)2 = a2 + 2ab + b2
(a − b)2 = a2 − 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
💡 Student Tip: Before solving any question, first rewrite the given number or expression into a suitable form (such as 100 + 10 + 7, 200 − 2, or a + b + c). Then identify the correct algebraic identity and apply it carefully to obtain the solution quickly and accurately.

📘 About Class 9 Maths Chapter 4 Exercise 4.3

Class 9 Maths Chapter 4 Exercise 4.3 focuses on the practical application of algebraic identities for expanding expressions, finding squares mentally, factorising perfect square expressions, and verifying identities. Students learn how to identify the most suitable identity before solving a question, which is the key objective of this exercise. These solutions follow the latest NCERT Ganita Manjari (2026) textbook and are fully aligned with the CBSE Class 9 syllabus and examination pattern.

🎯 What You’ll Learn

Learn how to choose the correct algebraic identity, calculate squares mentally, expand expressions involving two or three terms, factorise perfect square expressions, and verify algebraic identities using simple step-by-step methods.

📝 Why This Exercise Matters

This exercise develops logical thinking, pattern recognition, and algebraic manipulation skills. The concepts learned here are essential for polynomials, quadratic expressions, coordinate geometry, and many higher mathematics topics. Questions based on these identities are also frequently asked in CBSE examinations.

📚 Important Concepts Covered

✅ Choosing the Correct Algebraic Identity
✅ Identity (a + b)²
✅ Identity (a − b)²
✅ Identity (a + b + c)²
✅ Finding Squares Using Identities
✅ Factorisation of Perfect Square Expressions
✅ Expansion of Three-Term Expressions
✅ Verification of Algebraic Identities
✅ CBSE Exam-Oriented Problem Solving

📑 Table of Contents

Quickly navigate to any question of Class 9 Maths Chapter 4 Exercise 4.3 Solutions using the links below.

📝 Question 1

Find the squares using suitable algebraic identities.

🧮 Question 2

Factorise the following expressions.

✏️ Question 3

Expand the following expressions.

✅ Question 4

Verify the given algebraic identity.

⭐ Learn Before You Solve

Before solving Class 9 Maths Chapter 4 Exercise 4.3, learn how to identify the correct algebraic identity. Choosing the right identity first makes calculations easier, reduces mistakes, and helps you solve NCERT questions much faster.

① Rewrite First

Rewrite the given number or expression into a simple form before solving.

117 = 100 + 10 + 7
198 = 200 − 2
1104 = 1100 + 4

② Choose the Identity

✔ Two terms → (a + b)²
✔ Difference → (a − b)²
✔ Three terms → (a + b + c)²

③ Solve Carefully

Expand every term step by step. Don’t forget the cross terms like 2ab, 2bc and 2ca while using (a + b + c)².

💡 Quick Success Tips

  • Always identify the suitable identity before starting the calculation.
  • Write every intermediate step instead of solving mentally.
  • For three-term expressions, never miss any cross-product term.
  • After solving, compare your answer with the original expression to check correctness.

📝 Class 9 Maths Chapter 4 Exercise 4.3 Solutions

Solve every question of Class 9 Maths Chapter 4 Exercise 4.3 with simple, step-by-step NCERT Ganita Manjari (2026) solutions prepared in the latest CBSE answer-writing format.

📖 NCERT Solutions 📝 Step-by-Step 🎯 CBSE Ready
Question 1

Find the following squares using one of the above identities. Determine which of these identities will make these calculations easier.

(i)   1172
(ii)   782
(iii)   1982
(iv)   2142
(v)   11042
(vi)   11202
✅ Solution (i)
Sub Question
1172
Given
Find  1172
Step 1: Rewrite the number
117 = 100 + 10 + 7
Step 2: Choose the identity
Since the number is written as the sum of three terms, we use the identity
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Step 3: Substitute the values
a = 100
b = 10
c = 7
1172 = (100 + 10 + 7)2
Step 4: Perform the calculation
= 1002 + 102 + 72 + 2×100×10 + 2×10×7 + 2×100×7

= 10000 + 100 + 49 + 2000 + 140 + 1400

= 13689
Final Answer
1172 = 13689
✅ Solution (ii)
Sub Question
782
Given
Find  782
Step 1: Rewrite the number
78 = 80 − 2
Step 2: Choose the identity
Since the number is written as the difference of two terms, we use the identity
(a − b)2 = a2 − 2ab + b2
Step 3: Substitute the values
a = 80
b = 2
782 = (80 − 2)2
Step 4: Apply the identity and simplify
= 802 − 2 × 80 × 2 + 22

= 6400 − 320 + 4

= 6084
Final Answer
782 = 6084
✅ Solution (iii)
Sub Question
1982
Given
Find the square of 198 using a suitable algebraic identity.
Step 1: Rewrite the number
198 = 200 − 2
Step 2: Choose the identity
Since the number is written as the difference of two terms, we use the identity
(a − b)2 = a2 − 2ab + b2
Step 3: Substitute the values
a = 200
b = 2
1982 = (200 − 2)2
Step 4: Apply the identity and simplify
= 2002 − 2 × 200 × 2 + 22

= 40000 − 800 + 4

= 39204
Final Answer
1982 = 39204
✅ Solution (iv)
Sub Question
2142
Given
Find the square of 214 using a suitable algebraic identity.
Step 1: Rewrite the number
214 = 200 + 10 + 4
Step 2: Choose the identity
Since the number is written as the sum of three terms, we use the identity
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Step 3: Substitute the values
a = 200
b = 10
c = 4
2142 = (200 + 10 + 4)2
Step 4: Apply the identity and simplify
= 2002 + 102 + 42 + 2 × 200 × 10 + 2 × 10 × 4 + 2 × 200 × 4

= 40000 + 100 + 16 + 4000 + 80 + 1600

= 45796
Final Answer
2142 = 45796
✅ Solution (v)
Sub Question
11042
Given
Find the square of 1104 using a suitable algebraic identity.
Step 1: Rewrite the number
1104 = 1100 + 4
Step 2: Choose the identity
Since the number is written as the sum of two terms, we use the identity
(a + b)2 = a2 + 2ab + b2
Step 3: Substitute the values
a = 1100
b = 4
11042 = (1100 + 4)2
Step 4: Apply the identity and simplify
= 11002 + 2 × 1100 × 4 + 42

= 1210000 + 8800 + 16

= 1218816
Final Answer
11042 = 1218816
✅ Solution (vi)
Sub Question
11202
Given
Find the square of 1120 using a suitable algebraic identity.
Step 1: Rewrite the number
1120 = 1100 + 20
Step 2: Choose the identity
Since the number is written as the sum of two terms, we use the identity
(a + b)2 = a2 + 2ab + b2
Step 3: Substitute the values
a = 1100
b = 20
11202 = (1100 + 20)2
Step 4: Apply the identity and simplify
= 11002 + 2 × 1100 × 20 + 202

= 1210000 + 44000 + 400

= 1254400
Final Answer
11202 = 1254400
Question 2

Factor using suitable identities:

(i)    16y2 − 24y + 9
(ii)
9 4 s2 + 6st + 4 1 t2
(iii)
m2 9 + mk 3 + k2 4
(iv)
p2 16 16 p2
(v)    9a2 + 4b2 + c2 − 12ab + 6ac − 4bc
✅ Solution (i)
Sub Question
(i)  16y2 − 24y + 9
Given
The algebraic expression is
16y2 − 24y + 9
Identity Used
(a − b)2 = a2 − 2ab + b2
Step 1: Compare with the identity
a2 = 16y2
2ab = 24y
b2 = 9
Step 2: Identify the terms
a = 4y

b = 3
Step 3: Write the factorised form
16y2 − 24y + 9
=
(4y − 3)2
Final Answer
16y2 − 24y + 9 = (4y − 3)2
✅ Solution (ii)
Sub Question
(ii)   9 4 s2 + 6st + 4t2
Given
The algebraic expression is
9 4 s2 + 6st + 4t2
Identity Used
(a + b)2 = a2 + 2ab + b2
Step 1: Compare with the identity
a2 = 9 4 s2
2ab = 6st
b2 = 4t2
Step 2: Identify the terms
a = 3 2 s

b = 2t
Step 3: Write the factorised form
9 4 s2 + 6st + 4t2
=
( 3 2 s + 2t )2
Final Answer
9 4 s2 + 6st + 4t2
=
( 3 2 s + 2t )2
✅ Solution (iii)
Sub Question
(iii) m2 9 + mk 3 + k2 4
Given
m2 9 + mk 3 + k2 4
Identity Used
(a + b)2 = a2 + 2ab + b2
Step 1: Compare with the identity
a² = m2 9

2ab = mk 3

b² = k2 4
Step 2: Identify the terms
a = m 3

b = k 2
Step 3: Verify the middle term
2 × m 3 × k 2 = mk 3
Final Answer
( m 3 + k 2 )2
✅ Solution (iv)
Sub Question
(iv)   p2 16 − 2 + 16 p2
Given
p2 16 − 2 + 16 p2
Identity Used
(a − b)2 = a2 − 2ab + b2
Step 1: Compare with the identity
a2 = p2 16

2ab = 2

b2 = 16 p2
Step 2: Identify the terms
a = p 4

b = 4 p
Step 3: Verify the middle term
2ab = 2 × p 4 × 4 p

= 2 × 1

= 2 ✓
Step 4: Write the factorised form
p2 16 − 2 + 16 p2

=

( p 4 4 p )2
Final Answer
( p 4 4 p )2
✅ Solution (v)
Sub Question
(v)
9a2 + 4b2 + c2 − 12ab + 6ac − 4bc
Given
9a2 + 4b2 + c2 − 12ab + 6ac − 4bc
Identity Used
(x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2zx
Step 1: Compare with the identity
x2 = 9a2
y2 = 4b2
z2 = c2
2xy = −12ab
2yz = −4bc
2zx = 6ac
Step 2: Identify the terms
x = 3a      y = −2b   ← Terms containing b are negative, so y = −2b.      z = c
Step 3: Verify the middle terms
2 × 3a × (−2b) = −12ab ✓
2 × (−2b) × c = −4bc ✓
2 × c × 3a = 6ac ✓
Step 4: Write the factorised form
9a2 + 4b2 + c2 − 12ab + 6ac − 4bc

= (x + y + z)2

= (3a − 2b + c)2
Final Answer
9a2 + 4b2 + c2 − 12ab + 6ac − 4bc

= (3a − 2b + c)2
📘 Question 3
Expand this using the identity
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Sub Questions
(i)
(p + 3q + 7r)2
(ii)
(3x − 2y + 4z)2
✅ Solution (i)
Sub Question
(i)
(p + 3q + 7r)2
Given
(p + 3q + 7r)2
Identity Used
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Step 1: Compare with the identity
a = p
b = 3q
c = 7r
Step 2: Substitute the values
(p + 3q + 7r)2

= p2 + (3q)2 + (7r)2

+ 2(p)(3q) + 2(3q)(7r) + 2(7r)(p)
Step 3: Simplify
(p + 3q + 7r)2

= p2 + 9q2 + 49r2 + 6pq + 42qr + 14pr
Final Answer
(p + 3q + 7r)2

= p2 + 9q2 + 49r2 + 6pq + 42qr + 14pr
✅ Solution (ii)
Sub Question
(ii)
(3x − 2y + 4z)2
Given
(3x − 2y + 4z)2
Identity Used
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Step 1: Compare with the identity
a = 3x
b = −2y  ← Terms containing y are negative.
c = 4z
Step 2: Substitute the values
(3x − 2y + 4z)2

= (3x)2 + (−2y)2 + (4z)2

+ 2(3x)(−2y) + 2(−2y)(4z) + 2(4z)(3x)
Step 3: Simplify
(3x − 2y + 4z)2

= 9x2 + 4y2 + 16z2 − 12xy − 16yz + 24xz
Final Answer
(3x − 2y + 4z)2

= 9x2 + 4y2 + 16z2 − 12xy − 16yz + 24xz
📘 Question 4
Is this an identity?
(a + b − c)2 + (a − b + c)2 + (a − b − c)2 = 2a2 + 2b2 + 2c2
✅ Solution
Step 1: Expand each square
(a + b − c)2 = a2 + b2 + c2 + 2ab − 2ac − 2bc

(a − b + c)2 = a2 + b2 + c2 − 2ab + 2ac − 2bc

(a − b − c)2 = a2 + b2 + c2 − 2ab − 2ac + 2bc
Step 2: Add all the three expressions
LHS

= 3a2 + 3b2 + 3c2 − 2ab − 2ac − 2bc
Step 3: Compare LHS and RHS
LHS = 3a2 + 3b2 + 3c2 − 2ab − 2ac − 2bc

RHS = 2a2 + 2b2 + 2c2

Therefore,

LHS ≠ RHS
Conclusion
The given statement is not an identity.

📚 Continue Learning

Continue learning Class 9 Maths Chapter 4 Exploring Algebraic Identities by moving to the previous or next exercise, or explore solutions from other NCERT Class 9 Maths chapters.

📖 Explore More NCERT Class 9 Maths Solutions

🚀 Quick Revision Dashboard

Revise the important concepts of Class 9 Maths Chapter 4 Exercise 4.3 Solutions in just a few minutes. This quick revision guide will help you identify the correct algebraic identity, avoid common mistakes, and solve NCERT questions confidently in the CBSE examination.

📌 Identity Selection Guide

100 + 10 + 7 → (a + b + c)²
200 − 2 → (a − b)²
1100 + 4 → (a + b)²
a² − b² → (a + b)(a − b)

❌ Common Mistakes

  • Choosing the wrong identity.
  • Not rewriting the number first.
  • Missing 2ab, 2bc or 2ca.
  • Making sign mistakes in (a − b)².
  • Skipping intermediate steps.

📖 Formula Sheet

(a + b)2 = a2 + 2ab + b2

(a − b)2 = a2 − 2ab + b2

(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

a2 − b2 = (a + b)(a − b)

🎯 CBSE Exam Tips

  • Rewrite every number into a convenient form before applying an identity.
  • Identify the correct identity first, then substitute the values.
  • Write every calculation step clearly to score full marks.
  • Always check the signs while using (a − b)².
  • Revise all four algebraic identities before attempting Exercise 4.3.

❓ Frequently Asked Questions

Find quick answers to the most common doubts related to Class 9 Maths Chapter 4 Exercise 4.3 Solutions. These FAQs will help you understand algebraic identities, choose the correct identity, and prepare better for your CBSE Class 9 Mathematics examination.

What is the main concept of Class 9 Maths Chapter 4 Exercise 4.3?

Exercise 4.3 focuses on the application of algebraic identities. Students learn to find squares quickly, expand algebraic expressions, factorise perfect square expressions, and verify identities using standard formulas.

Which algebraic identities are used in Exercise 4.3?

The most important identities are (a + b)², (a − b)², (a + b + c)², and a² − b² = (a + b)(a − b). Choosing the correct identity is the key to solving every question accurately.

How can I identify the correct algebraic identity?

First rewrite the given number or expression into a suitable form. For example, write 198 = 200 − 2 or 117 = 100 + 10 + 7. Then compare it with the standard identities and apply the matching one.

Are these Class 9 Maths Chapter 4 Exercise 4.3 solutions based on the latest NCERT book?

Yes. All solutions are prepared according to the latest NCERT Ganita Manjari (2026) textbook and follow the current CBSE Class 9 Mathematics syllabus and answer-writing format.

Is Exercise 4.3 important for the CBSE Class 9 exam?

Yes. Exercise 4.3 is one of the most important exercises in Chapter 4 because it develops the ability to apply algebraic identities correctly. These concepts are frequently used in school examinations and also form the foundation for higher algebra in future classes.

🔗 Useful Learning Resources

Explore these trusted resources to strengthen your understanding of Class 9 Maths Chapter 4 Exercise 4.3 and continue your learning journey.

Need Personal Guidance in Maths?

Join Newton Study Point for concept-based Maths coaching by an experienced teacher. Small batches, individual attention, regular tests, and complete CBSE exam preparation for Classes 8, 9, 10, 11 & 12.

📞 Call Now: 8447002272 💬 WhatsApp

📍 Newton Study Point • Ankur Vihar, Ghaziabad

Rakesh Kumar Singh - Maths Educator
👨‍🏫 Reviewed & Prepared By

Rakesh Kumar Singh

Founder, Maths Gurukulam & Newton Study Point
Teaching CBSE Mathematics Since 2006

These Class 9 Maths Chapter 4 Exercise 4.3 Solutions are carefully prepared according to the latest NCERT Ganita Manjari (2026) and the CBSE curriculum. Every solution follows a clear, step-by-step approach designed to strengthen conceptual understanding, improve problem-solving skills, and help students perform confidently in school and board examinations.

📘 NCERT Ganita Manjari 2026 🎯 CBSE Aligned 📝 Step-by-Step Solutions 💡 Concept-Based Learning
Know More About the Author →

Leave A Reply

Your email address will not be published. Required fields are marked *

You May Also Like