📚 Table of Contents
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📍 About Class 9 Maths Chapter 1 Exercise 1.1
Learn Class 9 Maths Chapter 1 Exercise 1.1 Solutions with simple step-by-step explanations prepared according to the latest NCERT Ganita Manjari (2026) textbook and the CBSE Class 9 Mathematics syllabus.
Class 9 Maths Chapter 1 Exercise 1.1 Solutions are provided here with clear and student-friendly explanations based on the latest NCERT Ganita Manjari (2026). This exercise introduces the basic concepts of coordinate geometry through the real-life example of Reiaan’s room, helping students understand coordinates, distance from the axes, and positions on the coordinate plane with confidence.
🎯 Why Class 9 Maths Chapter 1 Exercise 1.1 is Important
Coordinates
Understand how coordinates are used to locate the exact position of any point on a plane.
Distance from Axes
Learn how to determine the distance of a point from the x-axis and y-axis using its coordinates.
Real-Life Application
The room layout activity helps students connect coordinate geometry with everyday situations.
🧠 Learn Before You Solve
Before solving Class 9 Maths Chapter 1 Exercise 1.1, quickly revise these important concepts from the chapter.
A coordinate system helps us locate the exact position of any object or point using numbers.
The point where the x-axis and y-axis intersect is called the origin.
The horizontal number line represents the x-axis.
The vertical number line represents the y-axis.
Every point is written as (x, y), where x represents the horizontal position and y represents the vertical position.
Right and upward directions are positive, while left and downward directions are negative.
The x-coordinate gives the distance from the y-axis, and the y-coordinate gives the distance from the x-axis.
Exercise 1.1 uses a room layout to explain coordinates through practical, real-life examples.
📖 Class 9 Maths Chapter 1 Exercise 1.1 Solutions
Step-by-step solutions based on the latest NCERT Ganita Manjari (2026) textbook and aligned with the CBSE Class 9 Mathematics syllabus. Every question is explained in a simple, student-friendly manner following the NCERT answer-writing pattern.
📌 Refer to Fig. 1.3 and answer the following questions:
- If D₁R₁ represents the door to Reiaan’s room, how far is the door from the left wall (the y-axis) of the room? How far is the door from the x-axis?
- What are the coordinates of D₁?
- If R₁ is the point (11.5, 0), how wide is the door? Do you think this is a comfortable width for the room door? If a person in a wheelchair wants to enter the room, will he/she be able to do so easily?
- If B₁ (0, 1.5) and B₂ (0, 4) represent the ends of the bathroom door, is the bathroom door narrower or wider than the room door?
📋 Given
Figure 1.3 represents Reiaan’s room on the Cartesian plane with all important points marked using coordinates.
🎯 To Find
- Distance from the x-axis and y-axis
- Coordinates of D₁
- Width of the room door
- Comparison of the bathroom and room door widths
The image below provides a complete overview of the solution for all parts of Question 1. Students can quickly understand the complete answer before studying the detailed step-by-step solution given below.
Point R₁ = (11.5, 0)
• the y-axis (left wall)
• the x-axis
x-coordinate = 8
y-coordinate = 0
∴ Distance from the y-axis = 8 units
• Distance from the x-axis = y-coordinate
∴ Distance from the x-axis = 0 units
✔ 8 units from the left wall (y-axis).
✔ 0 units from the x-axis.
Distance from x-axis = 0 units
• Distance of a point from the x-axis is its y-coordinate.
y-axis → x-coordinate
x-axis → y-coordinate
Therefore,
Hence,
• x is the horizontal distance from the y-axis.
• y is the vertical distance from the x-axis.
R₁ = (11.5, 0)
= 11.5 − 8
= 3.5 units
A door of this width is sufficiently wide for comfortable entry and exit.
Therefore, yes, a wheelchair user will be able to enter the room easily.
✔ The door is comfortable for regular use.
✔ A person in a wheelchair can enter the room easily.
B₁ = (0, 1.5)
B₂ = (0, 4)
Width of room door = 3.5 units
= 4 − 1.5
= 2.5 units
Width of bathroom door = 2.5 units
Since
✔ Width of the room door = 3.5 units.
✔ Therefore, the bathroom door is narrower than the room door.
| Part | Answer |
|---|---|
| (i) | Door is 8 units from the y-axis and 0 units from the x-axis. |
| (ii) | Coordinates of D₁ = (8, 0) |
| (iii) | Width of room door = 3.5 units. It is comfortable and wheelchair-friendly. |
| (iv) | Bathroom door width = 2.5 units. It is narrower than the room door. |
• Distance from the y-axis = x-coordinate.
• Distance from the x-axis = y-coordinate.
• Horizontal distance = Difference of x-coordinates.
• Vertical distance = Difference of y-coordinates.
📚 Continue Learning
Continue your Class 9 Maths Chapter 1 – Coordinates journey by solving the next exercise or exploring other NCERT chapter solutions.
🚀 Quick Revision Dashboard
Revise Question 1 of Class 9 Maths Chapter 1 Exercise 1.1 in one minute with these important coordinate geometry concepts.
📖 Important Rules
Distance from x-axis = y-coordinate
💡 Always Remember
- Coordinates are written as (x, y).
- Write the x-coordinate first.
- Points on the x-axis have y = 0.
- Points on the y-axis have x = 0.
❌ Avoid These Mistakes
- Interchanging the x and y coordinates.
- Using addition instead of difference to find width.
- Ignoring that points lie on the same axis.
- Writing coordinates in the wrong order.
🎯 Exam Tip
First identify whether the points lie on the x-axis or the y-axis. Then use the corresponding coordinate to find the required distance or width.
❓ Frequently Asked Questions
Find answers to the most common questions about Class 9 Maths Chapter 1 Exercise 1.1 Question 1 Solutions, coordinates, and distance from the x-axis and y-axis.
1. How do you find the distance of a point from the x-axis?
The distance of a point from the x-axis is equal to the absolute value of its y-coordinate. For points on the x-axis, the distance is 0.
2. How do you find the distance of a point from the y-axis?
The distance of a point from the y-axis is equal to the absolute value of its x-coordinate. For points on the y-axis, the distance is 0.
3. What is the coordinate form of a point?
A point is represented in the form (x, y), where x is the horizontal distance from the origin and y is the vertical distance from the origin.
4. How do you calculate the width between two points on the same axis?
If two points lie on the same horizontal or vertical line, subtract their corresponding coordinates. The difference gives the distance or width between the two points.
5. Which chapter does Exercise 1.1 belong to?
Exercise 1.1 belongs to Chapter 1 – Coordinates of the NCERT Class 9 Mathematics (Ganita Manjari 2026) textbook prescribed by CBSE.
6. Are these Class 9 Maths Chapter 1 Exercise 1.1 solutions based on the latest NCERT book?
Yes. These solutions are prepared according to the latest NCERT Ganita Manjari (2026) textbook and fully follow the CBSE Class 9 syllabus.
7. Are these solutions useful for CBSE exams?
Yes. Every solution is explained step by step in a simple CBSE answer-writing format, making it useful for homework, classroom learning, revision, and annual examinations.
8. What are the common mistakes students make in coordinate geometry?
Students often interchange the x-coordinate and y-coordinate, forget that points on the x-axis have y = 0 and points on the y-axis have x = 0, or use addition instead of finding the difference while calculating distances.
🔗 Useful Learning Resources
Explore these trusted resources to strengthen your understanding of Class 9 Maths Chapter 4 Exercise 4.3.
🏛 Official Resources
📚 Maths Gurukulam Resources
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These Class 9 Maths Chapter 1 Exercise 1.1 Solutions are carefully prepared according to the latest NCERT Ganita Manjari (2026) and the CBSE curriculum. Every solution follows a clear, step-by-step approach designed to strengthen conceptual understanding, improve problem-solving skills, and help students perform confidently in school and board examinations.