Class 9 Maths Chapter 13 Exercise 13.3 Solutions on slope and rise over run

Class 9 Maths Chapter 13 Exercise 13.3 Solutions – Two Variables, One Line

📘 Ganita Manjari Part II 📚 CBSE 2026–27 🏆 Step-by-Step Solutions

Class 9 Maths Chapter 13 Exercise 13.3 Solutions

Two Variables, One Line — Slope and Steepness

Find complete Class 9 Maths Chapter 13 Exercise 13.3 Solutions based on Ganita Manjari Grade 9 Part II (2026–27). This exercise focuses on the slope of a straight line and how slope describes steepness. Follow clear, step-by-step solutions to compare ski hills, calculate the slope of a ramp, find slopes from the given diagrams, and solve practical ramp problems. Use these NCERT-style textbook explanations for homework, concept revision and independent study.

📖
Exercise
Set 13.3
❓
Questions
4 Main Questions
📐
Main Concept
Slope of a Straight Line
↗️
Key Skill
Rise ÷ Run
📊
Diagram Skills
Read and Calculate Slopes
🛝
Real-Life Application
Ski Hills and Ramps
🎯 By the End of Exercise Set 13.3,
You Will Be Able To…
✅ Understand how slope describes the steepness of a line.
✅ Calculate slope using the vertical rise and horizontal run.
✅ Compare ski hills and arrange them by increasing steepness.
✅ Find the slope of a line from the textbook diagrams.
✅ Calculate the slope of a ramp using its rise and run.
✅ Apply the concept of slope to practical problems step by step.

📚 Exercise 13.3 — Table of Contents

📖 About Class 9 Maths Chapter 13 Exercise 13.3

Class 9 Maths Chapter 13 Exercise 13.3 Solutions cover Exercise Set 13.3 from Chapter 13 – Two Variables, One Line in the Ganita Manjari Grade 9 Part II textbook for the 2026–27 academic session. This exercise focuses on the slope of a straight line and how slope describes the steepness of a line or ramp. These step-by-step solutions help students compare ski hills, calculate the slope of a ramp, find slopes from diagrams, and understand practical applications of slope. The page supports students looking for Class 9 Maths Exercise 13.3 Solutions and Class 9 Maths Chapter 13 Solutions.

In Exercise 13.3, students explore how the vertical change and horizontal change of a line are used to calculate its slope. The key relationship is slope = vertical change ÷ horizontal change. Students use this relationship to compare steepness, calculate the slope of a ramp, and interpret information shown in diagrams. The worked solutions explain the mathematical steps clearly and connect straight-line slope with real-life situations such as ski hills and ramps.

🎯 Exercise 13.3 Snapshot

📘 What You’ll Find
  • Step-by-step solutions for the four main questions in Exercise Set 13.3.
  • Calculations involving the slope of a straight line.
  • Worked examples involving ski hills, diagrams and ramps.
📚 Skills You Practise
  • Using vertical change and horizontal change to calculate slope.
  • Comparing the steepness of different lines and ski hills.
  • Finding the slope of a ramp and interpreting slope diagrams.
🏆 Best For
  • Students studying Ganita Manjari Grade 9 Part II (2026–27).
  • Homework, classroom practice and independent revision.
  • Building confidence in slope calculations and understanding steepness.

Ready to understand slope step by step?

Go to Exercise 13.3 Solutions

Step-by-step solutions • Slope • Steepness • Ramp Problems

📘 Learn Before You Solve • Ganita Manjari Part II • 2026–27

📚 Learn Before You Solve

Class 9 Maths Chapter 13 Section 13.3 — Slope-Intercept Form of a Linear Equation in Two Variables

Before studying Class 9 Maths Chapter 13.3, understand the meaning of slope, how rise and run determine the steepness of a straight line, how to calculate slope using two points, and how to identify the slope and y-intercept from the equation y = mx + d. This guide follows Section 13.3 of Ganita Manjari Part II, Grade 9, 2026–27, including positive, negative, zero and undefined slopes.

CONCEPT 1 · SECTION 13.3 · TEXTBOOK PAGES 94–96

Understanding Slope: Steepness, Rise and Run

Before learning the slope-intercept form of a linear equation, we first need to understand the steepness of a straight line. In mathematics, this steepness is called the slope or gradient. It tells us how much a line goes upward or downward as we move from left to right.

🎯 What will you learn?

By the end of this concept, you will be able to identify positive and negative slopes, understand rise and run, and calculate the slope of a line using two points.

1 What Does Slope Mean?

Imagine cycling on a road. On a nearly flat road, you can move without climbing much. On a steep uphill road, you have to work harder. The difference in steepness helps us understand the idea of slope.

A line’s slope describes how its vertical position changes as we move horizontally from one point to another. The direction in which the line goes tells us whether its slope is positive or negative.

⛰️ A steeper line

A larger vertical change compared with the same horizontal change means a greater magnitude of slope.

🛤️ A flatter line

A smaller vertical change compared with the same horizontal change means a smaller magnitude of slope.

2 Positive Slope and Negative Slope

To identify the slope, imagine moving along a line from left to right. Observe whether the line rises or falls.

Positive Slope

The line goes upward as we move from left to right.

x-axis y-axis Run Rise Upward from left to right
Positive slope: m > 0

Negative Slope

The line goes downward as we move from left to right.

x-axis y-axis Run Down Downward from left to right
Negative slope: m < 0
Remember the direction Read a line from left to right. If it rises, its slope is positive. If it falls, its slope is negative.

3 Understand Rise and Run

Consider two points on a straight line: A(x₁, y₁) and B(x₂, y₂). To measure the slope, compare the vertical change with the horizontal change between these points.

Reading the Coordinates

The vertical and horizontal changes are measured between the same two points.

x-axis y-axis A(x₁,y₁) B(x₂,y₂) Run = x₂ − x₁ Rise y₂ − y₁ x₁ x₂ y₁ y₂

Conceptual diagram: the run is horizontal, while the rise is vertical. Both changes connect the same pair of points.

🔵 Run — Horizontal Change

Run measures how far we move horizontally from the first point to the second point.

Run = x₂ − x₁

Moving right gives a positive run; moving left gives a negative run.

🟢 Rise — Vertical Change

Rise measures how much the vertical coordinate changes between the two points.

Rise = y₂ − y₁

Moving up gives a positive rise; moving down gives a negative rise.

4 Build the Slope Formula

The slope compares the vertical change with the horizontal change. Therefore, for two points A(x₁, y₁) and B(x₂, y₂), the slope is the rise divided by the run.

The General Formula for Slope

Slope = Rise ÷ Run m = y₂ − y₁ x₂ − x₁

The denominator must not be zero. If the two points have the same x-coordinate, the line is vertical and its slope is undefined.

A useful sign check For a line rising from left to right, rise and run have the same sign when the points are taken from left to right. For a line falling from left to right, rise and run have opposite signs.

5 Worked Example: Calculate the Slope

In Figure 13.7, the line passes through A(2, 0) and B(4, 3). Find the slope of the line.

Step-by-Step Calculation

A(2, 0), B(4, 3)

Step 1: Identify the coordinates.

x₁ = 2, y₁ = 0
x₂ = 4, y₂ = 3

Step 2: Calculate the rise.

Rise = y₂ − y₁
= 3 − 0 = 3

Step 3: Calculate the run.

Run = x₂ − x₁
= 4 − 2 = 2

Step 4: Divide rise by run.

Slope = Rise ÷ Run
= 3 2
Final Answer: Slope = 3 2

Visual Check

From A(2, 0), move 2 units to the right to reach the vertical projection of B. Then move 3 units upward to reach B(4, 3).

0 1 2 3 4 5 0 1 2 3 4 x-axis y-axis A(2,0) B(4,3) Run = 2 Rise = 3
Slope = 3 2 = 1.5

The line rises 3 units for every 2 units of horizontal movement to the right.

✓ What You Should Remember

1. Slope describes the steepness and direction of a straight line.

2. A line rising from left to right has positive slope; a line falling from left to right has negative slope.

3. Run is the horizontal change and rise is the vertical change.

4. Slope is the ratio of rise to run: m = y₂ − y₁ x₂ − x₁ , provided the run is not zero.

5. For A(2, 0) and B(4, 3), the slope is 3 2 .

Textbook connection: Ganita Manjari Part II, Grade 9, Chapter 13, Section 13.3.1, pages 94–96, Figures 13.5–13.7.

Not want to continue Concepts, Ready to understand Exercise solutions step by step?

Go to Exercise 13.3 Solutions

Step-by-step solutions • Slope • Steepness • Ramp Problems

CONCEPT 2 · SECTION 13.3 · PAGES 96–98

Calculating Slope Between Two Points

We know that slope is rise divided by run. Let us now discover two important facts: a straight line has a constant slope, and reversing the order of two points does not change that slope.

🎯 Learning goal

Understand constant slope, solve Examples 5 and 6, and learn why the order of the points does not matter.

1 One Straight Line, One Constant Slope

In Figure 13.8, the line through A(2, 0) and B(4, 3) continues beyond B. Compare the slope measured from A to B with the slope measured from B to D(8, 9).

Figure 13.8 — Same line, different intervals

x-axisy-axis A(2, 0) B(4, 3) C(6, 6) D(8, 9) Run = 2 Rise = 3 Figure 13.8 · Schematic coordinate plot

The plotted points lie on the same straight line. The coordinate spacing is schematic; the point labels give the textbook coordinates.

Using A and B

Rise = 3 − 0 = 3
Run = 4 − 2 = 2
m = 32

Using B and D

Rise = 9 − 3 = 6
Run = 8 − 4 = 4
m = 64 = 32
Conclusion: the slope remains constant along the same straight line.

💭 Think and Reflect · Page 97

1. On line AB, find the point whose x-coordinate is 8.

From the figure, the point is D(8, 9). The y-coordinate is 9.

2. Find the point whose y-coordinate is 6.

The point is C(6, 6). The x-coordinate is 6.

2 Example 5 — Find the Slope

The straight line passes through A(−1, 0), B(1, 2) and C(4, 5). Find its slope.

Figure 13.9 — Three points on a line

x-axisy-axis A(−1, 0) B(1, 2) C(4, 5) Run = 3 Rise = 3 Figure 13.9 · Coordinate plot

Solution — Use B and C

B(1, 2), C(4, 5)
Rise = 5 − 2 = 3
Run = 4 − 1 = 3
m = 5 − 24 − 1 = 33 = 1
Answer: the slope is 1.

Notice that the vertical and horizontal changes are equal.

3 Example 6 — A Negative Slope

The line passes through A(−4, 5) and B(−1, 2). Find its slope.

Figure 13.10 — The line falls from left to right

x-axisy-axis A(−4, 5) B(−1, 2) Run = 3 Down = 3 Figure 13.10 · Coordinate plot

Solution — From A to B

Rise = 2 − 5 = −3
Run = −1 − (−4) = 3
m = 2 − 5−1 − (−4) = −33 = −1
Answer: the slope is −1.

4 Does the Order of the Points Matter?

Now reverse the order: take B first and A second. Both differences change sign.

A to B

Rise = 2 − 5 = −3
Run = −1 − (−4) = 3
m = −33 = −1

B to A

Rise = 5 − 2 = 3
Run = −4 − (−1) = −3
m = 3−3 = −1
Key idea Reversing the points changes both signs, so the ratio stays the same.
−33 = 3−3 = −1

✓ Quick Revision

Constant slope: the slope is the same along a straight line.

Example 5: slope = 1.

Example 6: slope = −1.

Reversing points: both differences change signs, so the slope does not change.

Textbook connection: Ganita Manjari Part II, Grade 9, Chapter 13, Section 13.3.1, pages 96–98, Figures 13.8–13.10, Examples 5 and 6.

CONCEPT 3 · SECTION 13.3 · PAGES 98–99

Understanding the Slope-Intercept Form

A straight line can be written in a special form that tells us its slope and where it crosses the y-axis.

🎯 Learning goal

Understand y = mx + d, identify m and d, derive the slope relationship, and convert the general form into slope-intercept form.

1 What Does y = mx + d Mean?

Slope-Intercept Form

y = mx + d

m = Slope

It tells us how steep the line is. Slope is the change in y divided by the change in x.

m = Change in y Change in x

d = Y-intercept

It is the y-coordinate where the line crosses the y-axis.

When x = 0, y = d
Remember When x = 0, y = m × 0 + d = d. Therefore, the line crosses the y-axis at (0, d).

2 Identify the Slope and Y-intercept

Consider the equation:

y = 2x + 3
Compare: y = 2x + 3 with y = mx + d.
Coefficient of x: m = 2.
Constant term: d = 3.
Slope = 2; y-intercept = 3. The line crosses the y-axis at (0, 3).

3 How Is m Related to the Slope?

Suppose A(x₁, y₁) and B(x₂, y₂) lie on the line y = mx + d.

At A: y₁ = mx₁ + d
At B: y₂ = mx₂ + d

Subtract the first equation from the second. The constant d cancels out.

y₂ − y₁ = m(x₂ − x₁)

Divide both sides by (x₂ − x₁), where x₂ ≠ x₁.

m = y₂ − y₁ x₂ − x₁
Thus, m is exactly the slope of the straight line.

4 Convert ax + by + c = 0

If b ≠ 0, we can rearrange the general form of a linear equation to make y the subject.

Step 1: Start with ax + by + c = 0.
by = −ax − c
Step 2: Divide every term by b.
y = −a b x − c b

Compare this with y = mx + d.

Slope

m = −a b

Y-intercept

d = − c b

The condition b ≠ 0 is necessary because we divide by b.

✓ Quick Revision

Slope-intercept form: y = mx + d

m: slope of the line.

d: y-coordinate where the line crosses the y-axis.

Slope relationship: m = y₂ − y₁ x₂ − x₁

General form: when b ≠ 0, ax + by + c = 0 can be written as y = mx + d.

Textbook connection: Ganita Manjari Part II, Grade 9, Chapter 13, Understanding the Slope-Intercept Form, pages 98–99.

CONCEPT 4 · SECTION 13.3 · PAGES 99–100

Finding Slope and Intercept from an Equation

We can find the slope and y-intercept directly from an equation by rewriting it in the form y = mx + d.

🎯 Learning goal

Rewrite 5x + y = 3, identify its slope and intercept, make a table of values, and understand its graph.

1 Rewrite in Slope-Intercept Form

Given equation:

5x + y = 3
Step 1: Subtract 5x from both sides.
y = −5x + 3

Compare this with y = mx + d.

Slope (m)

m = −5

Y-intercept (d)

d = 3
The slope is −5, and the line crosses the y-axis at (0, 3).

2 Construct a Table of Values

Use y = −5x + 3. Choose values for x and calculate y.

x Calculation y Point
−1 5 + 3 8 (−1, 8)
0 0 + 3 3 (0, 3)
1 −5 + 3 −2 (1, −2)

Each ordered pair satisfies the equation y = −5x + 3.

3 Understand Figure 13.11

Plot the points (−1, 8), (0, 3) and (1, −2). Join them with a straight line and extend the line in both directions.

Figure 13.11 — Graph of 5x + y = 3

x-axis y-axis x y −2 −1 0 1 2 3 8 7 6 5 4 3 2 1 0 −1 (−1, 8) (0, 3) (1, −2) Figure 13.11 · Straight-line graph
What does the graph tell us?

Y-intercept: The line crosses the y-axis at (0, 3).

Negative slope: The line falls from left to right.

Straight line: All points satisfying the equation lie on the same line.

💭 Think and Reflect · Page 99

Use the equation y = −5x + 3 and the graph to think about the following.

1. What is the y-intercept?

The y-intercept is 3, so the line crosses the y-axis at (0, 3).

2. Does the line rise or fall as x increases?

It falls from left to right because its slope is negative (−5).

4 Interpret the Slope and Intercept

Negative slope

Here m = −5. As x increases by 1, y decreases by 5.

Δx = 1   ⇒   Δy = −5

Y-intercept

Here d = 3. When x = 0, y = 3.

(0, 3)
For y = −5x + 3, the slope is −5 and the y-intercept is 3.

✓ Quick Revision

Original equation: 5x + y = 3

Slope-intercept form: y = −5x + 3

Slope: m = −5

Y-intercept: d = 3, at (0, 3)

Graph: a straight line falling from left to right.

Textbook connection: Ganita Manjari Part II, Grade 9, Chapter 13, pages 99–100, Figure 13.11.

CONCEPT 5 · SECTION 13.3 · PAGES 100–101

Four Types of Slope

The slope tells us how a straight line behaves as we move from left to right. A line may rise, fall, remain horizontal, or be vertical.

🎯 Learning goal

Recognise positive, negative, zero and undefined slopes from equations and graphs.

1 Positive Slope

Rises from left to right

Consider the equation:

y = 2x + 1

Comparing with y = mx + d, we get m = 2. Since the slope is positive, the line rises as x increases.

x y −4−3−2−101234 76543210−1−2−3−4 (−2, −3) (0, 1) (2, 5)
Remember A positive slope means the line goes upward from left to right.

2 Negative Slope

Falls from left to right

Consider the equation:

y = −3x + 4

Comparing with y = mx + d, we get m = −3. Since the slope is negative, the line falls as x increases.

x y −4−3−2−101234 76543210−1−2−3−4 (−1, 7) (0, 4) (1, 1)
Remember A negative slope means the line goes downward from left to right.

3 Zero Slope

Horizontal line

Consider the equation:

y = 5

The value of y remains 5 for every value of x. Therefore, the graph is a horizontal line and its slope is 0.

xy −4−3−2−101234 76543210−1−2−3−4 y = 5 (-3, 5) (0, 5) (3, 5)
Remember A horizontal line has zero slope because there is no vertical change as x changes.

4 Undefined Slope

Vertical line

Consider the equation:

x = 2

The value of x remains 2 for every point on the line. The line is vertical, so its slope is undefined.

xy −4−3−2−101234 76543210−1−2−3−4 (2, 6) x = 2 (2, 2) (2, −2)
Remember A vertical line has undefined slope because the horizontal change is zero.

💭 Think and Reflect

1. Which type of slope gives a line that rises from left to right?

A positive slope.

2. What is the slope of the line y = 5?

Its slope is zero, because it is horizontal.

3. Why is the slope of x = 2 undefined?

It is a vertical line, so the horizontal change is zero. The slope calculation would require division by zero.

✓ Quick Revision

Type of slope Example Graph behaviour
Positive y = 2x + 1 Rises left to right
Negative y = −3x + 4 Falls left to right
Zero y = 5 Horizontal line
Undefined x = 2 Vertical line
Key idea: positive and negative slopes describe rising and falling lines. Horizontal lines have zero slope, while vertical lines have undefined slope.

Textbook connection: Ganita Manjari Part II, Grade 9, Chapter 13, pages 100–101, Figures 13.11–13.13.

QUICK REVISION DASHBOARD · SLOPE

Quick Revision: Slope of a Straight Line

Revise the formula, rise and run, slope-intercept form, slope and intercepts, and the four slope cases.

1. Slope Formula

The slope measures how much the y-coordinate changes compared with the x-coordinate between two points.

For A(x₁, y₁) and B(x₂, y₂):

m = y₂ − y₁x₂ − x₁

Example: A(1, 1), B(3, 5)

m = 5 − 13 − 1 = 42 = 2

Always subtract the y-coordinates in the same order as the x-coordinates. Here, the slope is positive because the line rises from left to right.
−4−3−2−101234 654321−1−2−3−4−5−6 xyO A(1, 1)B(3, 5)

2. Rise and Run

Rise = change in y (vertical change).

Run = change in x (horizontal change).

Slope = RiseRun

From A(1, 1) to B(3, 5), rise = 5 − 1 = 4 and run = 3 − 1 = 2.

m = 42 = 2

Move from left to right: go 2 units right and 4 units up. The line rises, so the slope is positive.
−4−3−2−101234 654321−1−2−3−4−5−6 xyO A(1, 1)B(3, 5)Run = 2Rise = 4

3. Slope-Intercept Form

y = mx + c

m is the slope; c is the y-intercept, where the line crosses the y-axis.

Example: y = 2x + 1

Here, m = 2 and c = 1. The line crosses the y-axis at (0, 1).

To identify the slope and y-intercept, compare the equation with y = mx + c. Keep the sign of each number.
−4−3−2−101234 654321−1−2−3−4−5−6 xyO (0, 1)(2, 5)y-intercept

4. Identify the Slope and Intercept

Compare each equation with y = mx + c.

EquationSlope (m)y-intercept (c)Meaning
y = 2x + 121Rises; crosses y-axis at (0, 1)
y = −3x + 4−34Falls; crosses y-axis at (0, 4)
y = 505Horizontal line
x = 2UndefinedNot applicableVertical line; not in y = mx + c form
Remember: In y = mx + c, the number multiplying x is the slope and the constant term is the y-intercept.

5. The Four Slope Cases

Use each graph to recognise the line’s behaviour. The plotted points sit exactly on the line and on the coordinate grid.

Positive slope

y = 2x + 1

The line rises from left to right. Here m = 2.

−4−3−2−101234654321−1−2−3−4−5−6xyO (−2, −3)(0, 1)(2, 5)
Negative slope

y = −3x + 4

The line falls from left to right. Here m = −3.

−4−3−2−101234654321−1−2−3−4−5−6xyO (0, 4)(1, 1)(2, −2)
Zero slope

y = 5

The line is horizontal. The y-coordinate stays 5, so m = 0.

−4−3−2−101234654321−1−2−3−4−5−6xyO (−3, 5)(0, 5)(3, 5)
Undefined slope

x = 2

The line is vertical. The x-coordinate stays 2, so the slope is undefined.

−4−3−2−101234654321−1−2−3−4−5−6xyO (2, 4)(2, 0)(2, −4)

30-Second Memory Check

Formula: slope = change in y ÷ change in x.

y = mx + c: m is slope; c is the y-intercept.

Positive: rises. Negative: falls. Zero: horizontal. Undefined: vertical.

Exam tip: A vertical line has undefined slope because its run is zero; division by zero is not defined.

📝 Class 9 Maths Chapter 13 Exercise 13.3 Solutions

Explore the complete Class 9 Maths Chapter 13 Exercise 13.3 Solutions from Ganita Manjari Part II (2026–27), with clear, step-by-step explanations in a student-friendly CBSE answer-writing format. This exercise focuses on slope and steepness, interpreting lines on graphs, comparing slopes, and applying slope to real-life situations such as wheelchair ramps.

📝 Step-by-Step Solutions 🎯 CBSE Aligned ⭐ Complete Exercise 13.3
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🔎 Jump to Any Question

Navigate the questions in Class 9 Maths Chapter 13 Exercise 13.3, from Two Variables, One Line. Jump directly to a question to review its step-by-step solution.

Main Question
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CHAPTER 13 • EXERCISE SET 13.3

Question 1 — Slope and Steepness

Class 9 Mathematics | NCERT Ganita Manjari Part II | 2026–27

1. The following diagrams represent ski hills. Rank the hills in order of their steepness, from least to greatest.

A

70 m 60 m

B

110 m 60 m

C

100 m 80 m
Hill A Rise = 60 m
Run = 70 m
Hill B Rise = 60 m
Run = 110 m
Hill C Rise = 80 m
Run = 100 m

Given

The vertical rise and horizontal run of each ski hill are given in the diagrams.

To Find

Rank the three hills in order of steepness, from least to greatest.

Solution

The steepness of a hill is measured by its slope.
Slope = Vertical rise Horizontal run

Step 1: Find the slope of Hill A.

Slope of A = 6070
= 67 ≈ 0.857

Step 2: Find the slope of Hill B.

Slope of B = 60110
= 611 ≈ 0.545

Step 3: Find the slope of Hill C.

Slope of C = 80100
= 45 = 0.8

Step 4: Compare the slopes.

Hill A 67 ≈ 0.857
Hill B 611 ≈ 0.545
Hill C 45 = 0.8
Comparing the decimal values,
0.545 < 0.8 < 0.857
Therefore, Hill B is the least steep, Hill C is steeper than Hill B, and Hill A is the steepest.
Final Answer The order of the hills from least to greatest steepness is:
B, C, A
Key Concept: A greater slope means greater steepness. Compare the ratio of vertical rise to horizontal run for each hill.
CHAPTER 13 • EXERCISE SET 13.3

Question 2 — Slope of a Ramp

Class 9 Mathematics | NCERT Ganita Manjari Part II | 2026–27

2. The ramp at a loading dock rises 2.5 metres over a run of 4 metres. Find the slope of the ramp.
DELIVERY 4 m 2.5 m

Loading dock ramp showing the vertical rise and horizontal run.

Given

Vertical rise = 2.5 metres
Horizontal run = 4 metres

To Find

The slope of the ramp.

Solution

The slope of a line is the ratio of its vertical rise to its horizontal run.
Slope = Rise Run

Step 1: Substitute the given values.

Slope = 2.5 4

Step 2: Simplify the fraction.

Since 2.5 = 25/10, we can write:
Slope = 2.5 4
= 25 40
= 5 8
= 0.625
Final Answer The slope of the ramp is
5 8 = 0.625
CHAPTER 13 • EXERCISE SET 13.3

Question 3 — Find the Slope

Class 9 Mathematics | NCERT Ganita Manjari Part II | 2026–27

3. Find the slope of the line l in each of the following diagrams.

Study each graph and identify whether the line is horizontal, downward-sloping, upward-sloping or vertical.

(i) Horizontal line

x y O l

Diagram (i): Line l is horizontal.

Solution

A horizontal line has no vertical rise. Its y-coordinate remains constant as we move from left to right.
Slope = Rise Run
= 0 Run
= 0
Final Answer (i) Slope = 0

(ii) Downward-sloping line

x y O l

Diagram (ii): Line l slopes downward from left to right.

Solution

From the graph, take two points on the line, for example (−3, 3) and (3, −3).
Slope = y₂ − y₁ x₂ − x₁
= −3 − 3 3 − (−3)
= −6 6
= −1
Final Answer (ii) Slope = −1

(iii) Upward-sloping line

x y O l

Diagram (iii): Line l slopes upward from left to right.

Solution

A positive slope means that the line rises as we move from left to right. Using the rise and run shown by the graph:
Slope = Rise Run
= 2 3
Final Answer (iii) Slope = 2 3

(iv) Vertical line

x y O l

Diagram (iv): Line l is vertical and parallel to the y-axis.

Solution

For a vertical line, the x-coordinate remains constant. Therefore, the horizontal run is zero.
Slope = Rise Run
= Rise 0
Division by zero is undefined. Hence, the slope of a vertical line is undefined.
Final Answer (iv) Slope is undefined.
Remember: A horizontal line has zero slope, a downward-sloping line has negative slope, an upward-sloping line has positive slope, and a vertical line has undefined slope.
CHAPTER 13 • EXERCISE SET 13.3

Question 4 — Accessibility Ramp

Class 9 Mathematics | NCERT Ganita Manjari Part II | 2026–27

4. An accessibility ramp for wheelchairs is to be made alongside the staircase. The guidelines given for the slope of the ramp is 1 cm vertical rise to 12 cm horizontal length. What should be the horizontal length of the ramp if the total height of the stairs is 18 cm?
A child using a wheelchair on an accessibility ramp alongside a staircase, with a brick wall and purple handrails.

An accessibility ramp alongside a staircase.

Given

Vertical rise = 18 cm
Guideline: 1 cm vertical rise for every 12 cm horizontal length.

To Find

The horizontal length of the ramp.

Solution

The slope is the ratio of vertical rise to horizontal run.
Slope = Rise Run

Step 1: Write the given ratio.

Slope = 1 12

Step 2: Let the horizontal length be x cm.

For a vertical rise of 18 cm, the slope is:
18 x = 1 12

Step 3: Cross-multiply and solve.

18 × 12 = x × 1
216 = x
x = 216 cm
Final Answer The horizontal length of the ramp should be
216 cm (or 2.16 m).

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You have completed the Class 9 Maths Chapter 13 Exercise 13.3 Solutions. Revisit an earlier exercise or explore more chapters from Two Variables, One Line and the Ganita Manjari course.

CHAPTER 13 · TWO VARIABLES, ONE LINE


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❓ Frequently Asked Questions

Find quick answers about Class 9 Maths Chapter 13 Exercise 13.3 Solutions from Ganita Manjari Part II (2026–27). These FAQs explain slope, steepness, graph interpretation, and real-life ramp problems for homework, revision, self-study, and CBSE examination preparation.

What is taught in Class 9 Maths Chapter 13 Exercise 13.3?

Exercise Set 13.3 of Chapter 13, Two Variables, One Line, focuses on slope and steepness. Students compare ski hills, calculate the slope of a ramp, find slopes from line diagrams, and apply slope to a practical wheelchair-ramp problem using the given rise and horizontal length.

What is the formula for slope in Class 9 Maths?

The slope is calculated by dividing the vertical change by the horizontal change.

Slope = Vertical change ÷ Horizontal change

For example, if a ramp rises 2.5 metres over a horizontal run of 4 metres, then

Slope = 2.5 ÷ 4 = 0.625

The slope is 0.625. Always use the vertical rise and horizontal run, not the length of the sloping surface.

How do you compare the steepness of two ski hills?

Calculate the slope of each hill using its vertical rise and horizontal run. Compare the resulting values.

A hill with a larger positive slope is steeper than a hill with a smaller positive slope. For example, if two hills rise the same height, the one with the shorter horizontal run has the greater slope.

How do you find the slope of a line from a graph?

Choose two clearly marked points on the line. Find the vertical change and the horizontal change between them, then divide the vertical change by the horizontal change.

Slope = Change in y ÷ Change in x

For a line that rises from left to right, the slope is positive. For a line that falls from left to right, the slope is negative. A horizontal line has slope zero, while a vertical line has no defined slope.

What is the slope of a horizontal line?

A horizontal line has no vertical change between any two distinct points on it. Therefore,

Slope = 0 ÷ Horizontal change = 0

The slope of every horizontal line is zero.

Can a vertical line have a slope?

A vertical line has zero horizontal change. Since slope requires division by the horizontal change, its slope is undefined.

Vertical line: Slope is undefined.

How do you solve a wheelchair-ramp slope problem?

Use the given vertical rise and horizontal length. In Exercise 13.3, the accessibility-ramp guideline is a vertical rise of 1 cm for every 12 cm of horizontal length.

If the total height is 18 cm, then

Horizontal length = 18 × 12 = 216 cm

Therefore, the required horizontal length is 216 cm, or 2.16 metres.

What does a negative slope mean on a graph?

A negative slope means the line falls from left to right. As the x-coordinate increases, the y-coordinate decreases. The slope is negative because the vertical change and horizontal change have opposite signs.

Why is slope important in real-life situations?

Slope describes how steep a surface or line is. It is useful for understanding roads, ski hills, loading ramps, wheelchair ramps, and other situations involving vertical rise and horizontal distance. A larger positive slope represents a steeper upward incline.

Are these Class 9 Maths Chapter 13 Exercise 13.3 Solutions based on Ganita Manjari Part II 2026–27?

These Class 9 Maths Chapter 13 Exercise 13.3 Solutions are prepared for Exercise Set 13.3 of Ganita Manjari Part II (2026–27), Chapter 13, Two Variables, One Line. The explanations cover slope calculations, steepness comparisons, graph-based questions, and practical ramp applications in a student-friendly format.

📚 Useful Learning Resources

Continue your preparation with more Class 9 Maths resources from Maths Gurukulam, or visit the official NCERT and CBSE websites for textbooks, syllabus information, and academic updates. Revise slope, steepness, and the graphical representation of linear equations to strengthen your understanding of Class 9 Maths Chapter 13 Exercise 13.3 Solutions from Ganita Manjari Part II (2026–27).

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Found Class 9 Maths Chapter 13 Exercise 13.3 Solutions helpful? For students who need personal support beyond self-study, join Newton Study Point for concept-based Maths coaching by an experienced teacher. Small batches, individual attention, regular tests, and complete CBSE exam preparation are available for Classes 8, 9, 10, 11 & 12.

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👨‍🏫 Reviewed & Prepared By

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These Class 9 Maths Chapter 13 Exercise 13.3 Solutions are carefully prepared according to Ganita Manjari Part II (2026–27) and the CBSE curriculum. The solutions follow a clear, step-by-step approach to help students understand slope, compare the steepness of lines, interpret graphical representations, and apply the concept of slope to practical situations such as ramps and ski hills.

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